Find index number using Chain base method
| Item\Year | 2011 | 2012 | 2013 | 2014 | 2015 |
| Wheat | 40 | 46 | 50 | 56 | 64 |
| Bajri | 20 | 30 | 36 | 42 | 54 |
| Chana | 50 | 64 | 80 | 96 | 112 |
Solution:Chain base method :Chain base index number `I=("Value of variable in current year (period)")/("Value of variable in preceding year (period)") xx 100`
| Item\Year | 2011 | 2012 | 2013 | 2014 | 2015 |
| Wheat | `(40)/(40)xx100=100` | `(46)/(40)xx100=115` | `(50)/(46)xx100=108.7` | `(56)/(50)xx100=112` | `(64)/(56)xx100=114.29` |
| Bajri | `(20)/(20)xx100=100` | `(30)/(20)xx100=150` | `(36)/(30)xx100=120` | `(42)/(36)xx100=116.67` | `(54)/(42)xx100=128.57` |
| Chana | `(50)/(50)xx100=100` | `(64)/(50)xx100=128` | `(80)/(64)xx100=125` | `(96)/(80)xx100=120` | `(112)/(96)xx100=116.67` |
| Total | 300 | 393 | 353.7 | 348.67 | 359.52 |
| Aggregate index number `=("Total")/3` | `300/3=100` | `393/3=131` | `353.7/3=117.9` | `348.67/3=116.22` | `359.52/3=119.84` |
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