1. Geometric Mean of `16a^4,81/b^4`
Solution:
The geometric mean of `16a^4` and `81/b^4`
`=sqrt(16a^4 xx 81/b^4)`
`=sqrt((1296a^4)/(b^4))`
`=(36a^2)/(b^2)`
2. If geometric mean `9x` and x is `6x^2`, find value of x
Solution:
The geometric mean of `9x` and `X` is `6x^2`
`6x^2=sqrt(9x xx X)`
`:. (6x^2)^2=9x xx X`
`:. 36x^4=9x xx X`
`:. X=(36x^4)/(9x)`
`:. X=4x^(3)`
This material is intended as a summary. Use your textbook for detail explanation.
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