1. Calculate Median from the following mixed data
Class | Frequency |
1 | 3 |
2 | 4 |
5 | 10 |
6 - 10 | 23 |
10 - 20 | 20 |
20 - 30 | 20 |
30 - 50 | 15 |
50 - 70 | 3 |
70 - 100 | 2 |
Solution:
Class `(1)` | Frequency `(f)` `(2)` | `cf` `(6)` |
1 | 3 | 3 |
2 | 4 | 7 |
5 | 10 | 17 |
6 - 10 | 23 | 40 |
10 - 20 | 20 | 60 |
20 - 30 | 20 | 80 |
30 - 50 | 15 | 95 |
50 - 70 | 3 | 98 |
70 - 100 | 2 | 100 |
--- | --- | --- |
| `n = 100` | ----- |
To find Median Class
= value of `(n/2)^(th)` observation
= value of `(100/2)^(th)` observation
= value of `50^(th)` observation
From the column of cumulative frequency `cf`, we find that the `50^(th)` observation lies in the class `10 - 20`.
`:.` The median class is `10 - 20`.
Now,
`:. L = `lower boundary point of median class `=10`
`:. n = `Total frequency `=100`
`:. cf = `Cumulative frequency of the class preceding the median class `=40`
`:. f = `Frequency of the median class `=20`
`:. c = `class length of median class `=10`
Median `M = L + (n/2 - cf)/f * c`
`=10 + (50 - 40)/20 * 10`
`=10 + (10)/20 * 10`
`=10 + 5`
`=15`
2. Calculate Median from the following mixed data
Class | Frequency |
2 | 1 |
3 | 2 |
4 | 2 |
5 - 9 | 8 |
10 - 14 | 15 |
15 - 19 | 8 |
20 - 29 | 4 |
Solution:
Class `(1)` | Frequency `(f)` `(2)` | `cf` `(6)` |
2 | 1 | 1 |
3 | 2 | 3 |
4 | 2 | 5 |
5 - 9 | 8 | 13 |
10 - 14 | 15 | 28 |
15 - 19 | 8 | 36 |
20 - 29 | 4 | 40 |
--- | --- | --- |
| `n = 40` | ----- |
To find Median Class
= value of `(n/2)^(th)` observation
= value of `(40/2)^(th)` observation
= value of `20^(th)` observation
From the column of cumulative frequency `cf`, we find that the `20^(th)` observation lies in the class `10 - 14`.
`:.` The median class is `9.5 - 14.5`.
Now,
`:. L = `lower boundary point of median class `=9.5`
`:. n = `Total frequency `=40`
`:. cf = `Cumulative frequency of the class preceding the median class `=13`
`:. f = `Frequency of the median class `=15`
`:. c = `class length of median class `=5`
Median `M = L + (n/2 - cf)/f * c`
`=9.5 + (20 - 13)/15 * 5`
`=9.5 + (7)/15 * 5`
`=9.5 + 2.3333`
`=11.8333`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then