Home > Calculus calculators > If sin(x)=1/2, then solve trignometric expression cos(x)csc(x) example

2. If sin(x)=1/2, then solve trignometric expression cos(x)csc(x) example ( Enter your problem )
  1. If `sin(x)=3/5`, solve `cos(x)csc(x)+tan(x)sec(x)`
  2. If `cos(x)=3/5`, solve `(1-sin(x))/cos(x)+cos(x)/(1-sin(x))`
  3. If `tan(x)=1/2`, solve `(1-tan^2(x))/(1+tan^2(x))+(2tan(x))/(1+tan^2(x))`
  4. If `cos(x)=3/5`, solve `(1-sin(x))/cos(x)+cos(x)/(1-sin(x))`
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  3. If `sin(x)=1/2`, then solve trignometric expression `cos(x)csc(x)`
  4. Find the values of all six trigonometric functions for the given point P(x,y)
  5. The terminal side of `theta` is given by an equation, find the values of all six trigonometric functions
  6. Find the values of all six trigonometric functions for the given angle `theta`

3. If `tan(x)=1/2`, solve `(1-tan^2(x))/(1+tan^2(x))+(2tan(x))/(1+tan^2(x))`
(Previous example)
4. Find the values of all six trigonometric functions for the given point P(x,y)
(Next method)

4. If `cos(x)=3/5`, solve `(1-sin(x))/cos(x)+cos(x)/(1-sin(x))`





4. If `cos(x)=3/5`, solve `(1-sin(x))/cos(x)+cos(x)/(1-sin(x))`

Solution:
`cos(x)=3/5` (given)

`(1-sin(x))/cos(x)+cos(x)/(1-sin(x))=?`

`cos(x)=3/5`, in Quadrant-1

`(1)` `sin^2(x)=1-cos^2(x)`

`=1-(3/5)^2`

`=1-9/25`

`=(25-9)/25`

`=16/25`

`:.sin(x)=sqrt(16/25)=4/5=4/5`


`1-sin(x)=1/5`
`1-sin(x)`

`=1-(4/5)`

`=1+(-4)/5`

`=1/5`


Now substitute all these expression values in
`(1-sin(x))/(cos(x))+(cos(x))/(1-sin(x))`

`=(1/5)/(3/5)+(3/5)/(1/5)`

`=1/3+3`

`=10/3`

`:. (1-sin(x))/cos(x)+cos(x)/(1-sin(x))=10/3`




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3. If `tan(x)=1/2`, solve `(1-tan^2(x))/(1+tan^2(x))+(2tan(x))/(1+tan^2(x))`
(Previous example)
4. Find the values of all six trigonometric functions for the given point P(x,y)
(Next method)





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