1. Find Constant term / independent term of `(2-3x)^5`Solution:`(2-3x)^5`
Suppose the constant term exists and it is `(r+1)^(th)` term
`"Here "a=2,b=-3x,n=5`
`T_(r+1)=((n),(r))a^(n-r)b^r`
`=((5),(r))(2)^(5-r)(-3x)^r`
`=((5),(r))(2)^(5-r)*(-3)^r*(x)^r`
`=((5),(r))(2)^(5-r)*(-3)^r*(x)^(r)`
Determine the value of `r` for the constant term
For the constant term, the power of `x` must be 0
`r=0`
To find `T_1`, we let `r=0`
`:. T_1=T_(0+1)`
`=((5),(0))(2)^5(-3x)^0`
`=1(2)^5(-3x)^0`
`=1(32)(1)`
`=32`
The constant term in the expansion of `(2-3x)^5` is `32`
2. Find Constant term / independent term of `(2x^2-3)^11`Solution:`(2x^2-3)^11`
Suppose the constant term exists and it is `(r+1)^(th)` term
`"Here "a=2x^2,b=-3,n=11`
`T_(r+1)=((n),(r))a^(n-r)b^r`
`=((11),(r))(2x^2)^(11-r)(-3)^r`
`=((11),(r))(2)^(11-r)*(x^2)^(11-r)*(-3)^r`
`=((11),(r))(2)^(11-r)*(-3)^r*(x^2)^(11-r)`
`=((11),(r))(2)^(11-r)*(-3)^r*(x)^(2(11-r))`
`=((11),(r))(2)^(11-r)*(-3)^r*(x)^(22-2r)`
Determine the value of `r` for the constant term
For the constant term, the power of `x` must be 0
`22-2r=0`
`2r=22`
`r=11`
To find `T_12`, we let `r=11`
`:. T_12=T_(11+1)`
`=((11),(11))(2x^2)^0(-3)^11`
`=1(2x^2)^0(-3)^11`
`=1(1)(-177147)`
`=-177147`
The constant term in the expansion of `(2x^2-3)^11` is `-177147`
3. Find Constant term / independent term of `(2x^2-1/x)^11`Solution:`(2x^2-1/x)^11`
Suppose the constant term exists and it is `(r+1)^(th)` term
`"Here "a=2x^2,b=-1/x,n=11`
`T_(r+1)=((n),(r))a^(n-r)b^r`
`=((11),(r))(2x^2)^(11-r)(-1/x)^r`
`=((11),(r))(2)^(11-r)*(x^2)^(11-r)*(-1)^r*(1/x)^r`
`=((11),(r))(2)^(11-r)*(-1)^r*(x^2)^(11-r)*(1/x)^r`
`=((11),(r))(2)^(11-r)*(-1)^r*(x)^(2(11-r))*(x)^(-r)`
`=((11),(r))(2)^(11-r)*(-1)^r*(x)^(22-2r-r)`
`=((11),(r))(2)^(11-r)*(-1)^r*(x)^(22-3r)`
Determine the value of `r` for the constant term
For the constant term, the power of `x` must be 0
`22-3r=0`
`3r=22`
`r=22/3`
Since `r` must be an integer, there is no term where the power of `x` is 0
constant term does not exist in the expansion
4. Find Constant term / independent term of `(2x^2-1/x^2)^11`Solution:`(2x^2-1/x^2)^11`
Suppose the constant term exists and it is `(r+1)^(th)` term
`"Here "a=2x^2,b=-1/(x^2),n=11`
`T_(r+1)=((n),(r))a^(n-r)b^r`
`=((11),(r))(2x^2)^(11-r)(-1/(x^2))^r`
`=((11),(r))(2)^(11-r)*(x^2)^(11-r)*(-1)^r*(1/(x^2))^r`
`=((11),(r))(2)^(11-r)*(-1)^r*(x^2)^(11-r)*(1/(x^2))^r`
`=((11),(r))(2)^(11-r)*(-1)^r*(x)^(2(11-r))*(x)^(-2r)`
`=((11),(r))(2)^(11-r)*(-1)^r*(x)^(22-2r-2r)`
`=((11),(r))(2)^(11-r)*(-1)^r*(x)^(22-4r)`
Determine the value of `r` for the constant term
For the constant term, the power of `x` must be 0
`22-4r=0`
`4r=22`
`r=11/2`
Since `r` must be an integer, there is no term where the power of `x` is 0
constant term does not exist in the expansion
This material is intended as a summary. Use your textbook for detail explanation.
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