1. Find Regression line equations from x = 39.5, y = 47.5, 6x = 10.8, 6y = 15, r = 0.42
Solution:
`byx = r * (sigma y)/(sigma x)`
`byx = 0.42 * 15/10.8`
`byx = 0.58`
Regression Line y on x
`y - bar y = byx (x - bar x)`
`y - 47.5 = 0.58 (x - 39.5)`
`y - 47.5 = 0.58 x - 23.04`
`y = 0.58 x - 23.04 + 47.5`
`y = 0.58 x + 24.46`
`bxy = r * (sigma x)/(sigma y)`
`bxy = 0.42 * 10.8/15`
`bxy = 0.3`
Regression Line x on y
`x - bar x = bxy (y - bar y)`
`x - 39.5 = 0.3 (y - 47.5)`
`x - 39.5 = 0.3 y - 14.36`
`x = 0.3 y - 14.36 + 39.5`
`x = 0.3 y + 25.14`
This material is intended as a summary. Use your textbook for detail explanation.
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