Solve Equations 2x+5y=16,3x+y=11 using Gauss-Jordan Elimination method
Solution:
Total Equations are `2`
`2x+5y=16 -> (1)`
`3x+y=11 -> (2)`
Converting given equations into matrix form
`R_1 larr R_1-:2`
= | | `1` `1=2-:2` `R_1 larr R_1-:2` | `5/2` `5/2=5-:2` `R_1 larr R_1-:2` | | `8` `8=16-:2` `R_1 larr R_1-:2` | | | `3` | `1` | | `11` | |
|
`R_2 larr R_2-3xx R_1`
= | | `1` | `5/2` | | `8` | | | `0` `0=3-3xx1` `R_2 larr R_2-3xx R_1` | `-13/2` `-13/2=1-3xx5/2` `R_2 larr R_2-3xx R_1` | | `-13` `-13=11-3xx8` `R_2 larr R_2-3xx R_1` | |
|
`R_2 larr R_2xx-2/13`
= | | `1` | `5/2` | | `8` | | | `0` `0=0xx-2/13` `R_2 larr R_2xx-2/13` | `1` `1=-13/2xx-2/13` `R_2 larr R_2xx-2/13` | | `2` `2=-13xx-2/13` `R_2 larr R_2xx-2/13` | |
|
`R_1 larr R_1-5/2xx R_2`
= | | `1` `1=1-5/2xx0` `R_1 larr R_1-5/2xx R_2` | `0` `0=5/2-5/2xx1` `R_1 larr R_1-5/2xx R_2` | | `3` `3=8-5/2xx2` `R_1 larr R_1-5/2xx R_2` | | | `0` | `1` | | `2` | |
|
`i.e.`
`x=3`
`y=2`
Solution By Gauss jordan elimination method.
`x = 3`
`y = 2`
This material is intended as a summary. Use your textbook for detail explanation.
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