1. `A=-1-i,B=-2+3i,C=1-3i`
Find arg(A)Solution:Here `A=-1-i,B=-2+3i,C=1-3i`
For a complex number `z=a+bi`, The argument is `theta=atan(b/a)`
Here, `a=-1` and `b=-1`
`theta=atan(b/a)+180` (Since `a<0`)
`:. theta=atan((-1)/(-1))+180`
`:. theta=atan(1)+180`
`:. theta=45+180`
`:. theta=225 ^circ` or `theta=(5pi)/(4)` rad = 3.927 rad
2. `A=5+6i,B=-2+3i,C=1-3i`
Find arg(A)Solution:Here `A=5+6i,B=-2+3i,C=1-3i`
For a complex number `z=a+bi`, The argument is `theta=atan(b/a)`
Here, `a=5` and `b=6`
`theta=atan(b/a)` (Since `a>0`)
`:. theta=atan((6)/(5))`
`:. theta=atan(1.2)`
`:. theta=50.1944 ^circ` or `theta=0.8761` rad
3. `A=-1-i,B=-2+3i,C=1-3i`
Find arg(B)Solution:Here `A=-1-i,B=-2+3i,C=1-3i`
For a complex number `z=a+bi`, The argument is `theta=atan(b/a)`
Here, `a=-2` and `b=3`
`theta=atan(b/a)+180` (Since `a<0`)
`:. theta=atan((3)/(-2))+180`
`:. theta=atan(-1.5)+180`
`:. theta=-56.3099+180`
`:. theta=123.6901 ^circ` or `theta=2.1588` rad
This material is intended as a summary. Use your textbook for detail explanation.
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