1. `A=5+6i`
Find Multiplicative inverse of complex numbersSolution:Here `A=5+6i`
For a complex number `z=a+bi`, the inverse is `z^(-1)=(a-bi)/(a^2+b^2)`
`z=a+bi`
`:. z^(-1)=1/(a+bi)`
`:. z^(-1)=1/((a+bi))*((a-bi))/((a-bi))`
`:. z^(-1)=(a-bi)/(a^2+b^2)`
`A=5+6i`
`:. A^(-1)=1/(5+6i)`
`=1/((5+6i))*((5-6i))/((5-6i))`
`=(5-6i)/(5^2+6^2)`
`=(5-6i)/(25+36)`
`=(5-6i)/61`
`=0.082-0.0984i`
`:.` The inverse of `5+6i` is `0.082-0.0984i`
2. `A=-2+3i`
Find Multiplicative inverse of complex numbersSolution:Here `A=-2+3i`
For a complex number `z=a+bi`, the inverse is `z^(-1)=(a-bi)/(a^2+b^2)`
`z=a+bi`
`:. z^(-1)=1/(a+bi)`
`:. z^(-1)=1/((a+bi))*((a-bi))/((a-bi))`
`:. z^(-1)=(a-bi)/(a^2+b^2)`
`A=-2+3i`
`:. A^(-1)=1/(-2+3i)`
`=1/((-2+3i))*((-2-3i))/((-2-3i))`
`=(-2-3i)/((-2)^2+3^2)`
`=(-2-3i)/(4+9)`
`=(-2-3i)/13`
`=-0.1538-0.2308i`
`:.` The inverse of `-2+3i` is `-0.1538-0.2308i`
3. `A=1-3i`
Find Multiplicative inverse of complex numbersSolution:Here `A=1-3i`
For a complex number `z=a+bi`, the inverse is `z^(-1)=(a-bi)/(a^2+b^2)`
`z=a+bi`
`:. z^(-1)=1/(a+bi)`
`:. z^(-1)=1/((a+bi))*((a-bi))/((a-bi))`
`:. z^(-1)=(a-bi)/(a^2+b^2)`
`A=1-3i`
`:. A^(-1)=1/(1-3i)`
`=1/((1-3i))*((1+3i))/((1+3i))`
`=(1+3i)/(1^2+3^2)`
`=(1+3i)/(1+9)`
`=(1+3i)/10`
`=0.1+0.3i`
`:.` The inverse of `1-3i` is `0.1+0.3i`
This material is intended as a summary. Use your textbook for detail explanation.Any bug, improvement, feedback then
Submit Here
