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12. Polar form of complex numbers example ( Enter your problem )
  1. Example-1
Other related methods
  1. Adding complex numbers
  2. Subtracting complex numbers
  3. Multiplying complex numbers
  4. Dividing complex numbers
  5. Real part of complex number
  6. Imaginary part of complex number
  7. Conjugate of complex number
  8. Modulus / Magnitude / Absolute value of complex numbers
  9. Multiplicative inverse of complex numbers
  10. Reciprocal of complex number
  11. Argument / Arg / Angle / Phase of complex number
  12. Polar form of complex numbers
  13. Exponential form of complex numbers
  14. Square root of complex number
  15. Cube root of complex number
  16. Powers of complex numbers
  17. Roots of complex numbers

11. Argument / Arg / Angle / Phase of complex number
(Previous method)
13. Exponential form of complex numbers
(Next method)

1. Example-1





1. `A=-1-i,B=-2+3i,C=1-3i`
Find polar(A)


Solution:
Here `A=-1-i,B=-2+3i,C=1-3i`


For a complex number `z=a+bi`, the polar form is `z=r*(cos(theta)+i*sin(theta))`

where `r=sqrt(a^2+b^2)` and `theta=atan(b/a)`


Here, `a=-1` and `b=-1`

`:. r=sqrt((-1)^2+(-1)^2)=sqrt(1+1)=sqrt(2)=1.4142`

`theta=atan(b/a)+180` (Since `a<0`)

`:. theta=atan((-1)/(-1))+180`

`:. theta=atan(1)+180`

`:. theta=45+180`

`:. theta=225 ^circ` or `theta=(5pi)/(4)` rad = 3.927 rad

`:.` The polar form (in degree) is `1.4142*(cos(225)+i*sin(225))`

`:.` The polar form (in radian) is `1.4142*(cos((5pi)/(4))+i*sin((5pi)/(4)))`
2. `A=5+6i,B=-2+3i,C=1-3i`
Find polar(A)


Solution:
Here `A=5+6i,B=-2+3i,C=1-3i`


For a complex number `z=a+bi`, the polar form is `z=r*(cos(theta)+i*sin(theta))`

where `r=sqrt(a^2+b^2)` and `theta=atan(b/a)`


Here, `a=5` and `b=6`

`:. r=sqrt(5^2+6^2)=sqrt(25+36)=sqrt(61)=7.8102`

`theta=atan(b/a)` (Since `a>0`)

`:. theta=atan((6)/(5))`

`:. theta=atan(1.2)`

`:. theta=50.1944 ^circ` or `theta=0.8761` rad

`:.` The polar form (in degree) is `7.8102*(cos(50.1944)+i*sin(50.1944))`

`:.` The polar form (in radian) is `7.8102*(cos(0.8761)+i*sin(0.8761))`
3. `A=-1-i,B=-2+3i,C=1-3i`
Find polar(B)


Solution:
Here `A=-1-i,B=-2+3i,C=1-3i`


For a complex number `z=a+bi`, the polar form is `z=r*(cos(theta)+i*sin(theta))`

where `r=sqrt(a^2+b^2)` and `theta=atan(b/a)`


Here, `a=-2` and `b=3`

`:. r=sqrt((-2)^2+3^2)=sqrt(4+9)=sqrt(13)=3.6056`

`theta=atan(b/a)+180` (Since `a<0`)

`:. theta=atan((3)/(-2))+180`

`:. theta=atan(-1.5)+180`

`:. theta=-56.3099+180`

`:. theta=123.6901 ^circ` or `theta=2.1588` rad

`:.` The polar form (in degree) is `3.6056*(cos(123.6901)+i*sin(123.6901))`

`:.` The polar form (in radian) is `3.6056*(cos(2.1588)+i*sin(2.1588))`


This material is intended as a summary. Use your textbook for detail explanation.
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11. Argument / Arg / Angle / Phase of complex number
(Previous method)
13. Exponential form of complex numbers
(Next method)





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