`f(x)=x^3-3x^2+7`
Find Increasing and decreasing functions at point x = 1,3Solution:Here, `f(x)=x^3-3x^2+7`
Step-1: Find the derivative of the function`:. f^'(x)=``d/(dx)(x^3-3x^2+7)`
`=d/(dx)(x^3)-d/(dx)(3x^2)+d/(dx)(7)`
`=3x^2-6x+0`
`=3x^2-6x`
Step-2: Determine if the function is increasing or decreasing at given points1. At `x=1``f^'(1)``=3*1^2-6*1`
`=3-6`
`=-3`` < 0`
`:.` Function is decreasing at `x=1`2. At `x=3``f^'(3)``=3*3^2-6*3`
`=27-18`
`=9`` > 0`
`:.` Function is increasing at `x=3`
This material is intended as a summary. Use your textbook for detail explanation.
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