`f(x)=x^3-3x+2`
Find Increasing and decreasing functions at point x = 0,2Solution:Here, `f(x)=x^3-3x+2`
Step-1: Find the derivative of the function`:. f^'(x)=``d/(dx)(x^3-3x+2)`
`=d/(dx)(x^3)-d/(dx)(3x)+d/(dx)(2)`
`=3x^2-3+0`
`=3x^2-3`
Step-2: Determine if the function is increasing or decreasing at given points1. At `x=0``f^'(0)``=3*0^2-3`
`=0-3`
`=-3`` < 0`
`:.` Function is decreasing at `x=0`2. At `x=2``f^'(2)``=3*2^2-3`
`=12-3`
`=9`` > 0`
`:.` Function is increasing at `x=2`
This material is intended as a summary. Use your textbook for detail explanation.
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