`f(x)=x^2-4x`
Find Increasing and decreasing functions at point x = -1,0,3Solution:Here, `f(x)=x^2-4x`
Step-1: Find the derivative of the function`:. f^'(x)=``d/(dx)(x^2-4x)`
`=d/(dx)(x^2)-d/(dx)(4x)`
`=2x-4`
Step-2: Determine if the function is increasing or decreasing at given points1. At `x=-1``f^'(-1)``=2*(-1)-4`
`=-2-4`
`=-6`` < 0`
`:.` Function is decreasing at `x=-1`2. At `x=0``f^'(0)``=2*0-4`
`=0-4`
`=-4`` < 0`
`:.` Function is decreasing at `x=0`3. At `x=3``f^'(3)``=2*3-4`
`=6-4`
`=2`` > 0`
`:.` Function is increasing at `x=3`
This material is intended as a summary. Use your textbook for detail explanation.
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