2. `y=(x+2)^2-9`, find Intercept of a function
Solution:
`y=(x+2)^2-9`
1. Intercepts :
Intercept :
To find the y-intercept put x=0 in `y=(x+2)^2-9`, we get
`y=(0+2)^2-9=4-9=-5`
`:.` y-intercept is `(0,-5)`
To find the x-intercept put y=0 in `y=(x+2)^2-9`, we get
`=>(x+2)^2-9=0`
`=>(x+2)^2=0+9`
`=>(x+2)^2=9`
`=>x+2=+- 3`
Now, `x+2=3`
`=>x=3-2`
`=>x=1`
Now, `x+2=-3`
`=>x=-3-2`
`=>x=-5`
`:.` x-intercepts are `(1,0)` and `(-5,0)`
This material is intended as a summary. Use your textbook for detail explanation.
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