`y=3(x+1)^2-4`, find Intercept of a function
Solution:
`y=3(x+1)^2-4`
1. Intercepts :
Intercept :
To find the y-intercept put x=0 in `y=3(x+1)^2-4`, we get
`y=3(0+1)^2-4=3(1)-4=-1`
`:.` y-intercept is `(0,-1)`
To find the x-intercept put y=0 in `y=3(x+1)^2-4`, we get
`=>3*(x+1)^2-4=0`
`=>3*(x+1)^2=4`
`=>(x+1)^2=4/3`
`=>x+1=+- 2/(sqrt(3))`
Now, `x+1=2/(sqrt(3))`
`=>x=2/(sqrt(3))-1`
`=>x=0.1547`
Now, `x+1=-2/(sqrt(3))`
`=>x=-2/(sqrt(3))-1`
`=>x=-2.1547`
`:.` x-intercepts are `(0.1547,0)` and `(-2.1547,0)`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then
