1. Examples
1. (567)8 = ( ? )16
Solution: `(567)_8 = (underline{" "})_16`
First convert octal to binary `(567)_8 = (underline{" "})_2`
`:. (567)_8 = (underline{101110111})_2`
Now convert binary to hexadecimal `(101110111)_2 = (underline{" "})_16`
`:. (101110111)_2 = (underline{177})_16`
`:. (567)_8 = (underline{177})_16`
2. (4321)8 = ( ? )16
Solution: `(4321)_8 = (underline{" "})_16`
First convert octal to binary `(4321)_8 = (underline{" "})_2`
`:. (4321)_8 = (underline{100011010001})_2`
Now convert binary to hexadecimal `(100011010001)_2 = (underline{" "})_16`
`:. (100011010001)_2 = (underline{8D1})_16`
`:. (4321)_8 = (underline{8D1})_16`
This material is intended as a summary. Use your textbook for detail explanation. Any bug, improvement, feedback then
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