1. (567)8 = ( ? )16Solution:`(567)_8 = (underline{" "})_16`
First convert octal to binary
`(567)_8 = (underline{" "})_2``:. (567)_8 = (underline{101110111})_2`
Now convert binary to hexadecimal
`(101110111)_2 = (underline{" "})_16``:. (101110111)_2 = (underline{177})_16`
`:. (567)_8 = (underline{177})_16`
2. (4321)8 = ( ? )16Solution:`(4321)_8 = (underline{" "})_16`
First convert octal to binary
`(4321)_8 = (underline{" "})_2``:. (4321)_8 = (underline{100011010001})_2`
Now convert binary to hexadecimal
`(100011010001)_2 = (underline{" "})_16``:. (100011010001)_2 = (underline{8D1})_16`
`:. (4321)_8 = (underline{8D1})_16`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then