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6. Quadratic Equation - Roots for non-zero denominator example ( Enter your problem )
  1. Example-1 : `(5x-18)/(x+2)=(2x-6)/(x-1)`
  2. Example-2 : `(x)/(x+1)+(x+1)/(x)=5/2`
  3. Example-3 : `4((4x+1)/(4x-1))^(2)+(4x+1)/(4x-1)=3`
  4. Example-4 : `(4x+1)/(4x-1)+(4x-1)/(4x+1)=3`

2. Example-2 : `(x)/(x+1)+(x+1)/(x)=5/2`





2. Find roots of the equation `(x)/(x+1) + (x+1)/(x) = (5)/(2)`

` (x)/(x+1) + (x+1)/(x) = (5)/(2)`

` => (x)*(x)*(2) + (x+1)*(x+1)*(2) = (5)*(x+1)*(x)`

` => 2x^2 + (2x^2+4x+2) = (5x^2+5x)`

` => 2x^2 + (2x^2+4x+2) + (-5x^2-5x) = 0`

` => -x^2-x+2 = 0`

` => (-x^2-x+2) = 0`

` => -x^2-x+2 = 0`

` => (-1)(x^2+x-2) = 0`

` => (-1)(x^2-x+2x-2) = 0`

` => (-1)(x(x-1)+2(x-1)) = 0`

` => (-1)(x+2)(x-1) = 0`

` => (x+2) = 0" or "(x-1) = 0`

` => x = -2" or "x = 1`






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