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6. Quadratic Equation - Roots for non-zero denominator example ( Enter your problem )
  1. Example-1 : `(5x-18)/(x+2)=(2x-6)/(x-1)`
  2. Example-2 : `(x)/(x+1)+(x+1)/(x)=5/2`
  3. Example-3 : `4((4x+1)/(4x-1))^(2)+(4x+1)/(4x-1)=3`
  4. Example-4 : `(4x+1)/(4x-1)+(4x-1)/(4x+1)=3`

4. Example-4 : `(4x+1)/(4x-1)+(4x-1)/(4x+1)=3`





4. Find roots of the equation `12((x)/(x-1)) + 12((x-1)/(x)) = 25`

` 12((x)/(x-1)) + 12((x-1)/(x)) = 25`

` "Let " (x)/(x-1) = m`

` => 12m + 12/m = 25`

` => 12m^2 - 25m + 12 = 0`

` => (12m^2-25m+12) = 0`

` => 12m^2-25m+12 = 0`

` => (12m^2-25m+12) = 0`

` => (12m^2-9m-16m+12) = 0`

` => 3m(4m-3)+(-4)(4m-3) = 0`

` => (3m-4)(4m-3) = 0`

` => (3m-4) = 0" or "(4m-3) = 0`

` => 3m = 4" or "4m = 3`

` => m = 4/3" or "m = 3/4`

` " Now," (x)/(x-1) = 4/3`

` => 3(x) = 4(x-1)`

` => 3(x) - 4(x-1) = 0`

` => (3x-4(x-1)) = 0`

` => (-x+4) = 0`

` => x = 4`

` " Now," (x)/(x-1) = 3/4`

` => 4(x) = 3(x-1)`

` => 4(x) - 3(x-1) = 0`

` => (4x-3(x-1)) = 0`

` => (x+3) = 0`

` => x = -3`






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