1. Find Angle between two vectors
`A=(3,4,0)`, `B=(2,2,1)`

Solution:
Here `vec A=(3,4,0),vec B=(2,2,1)`

The angle between two vectors `vec A` and `vec B` is given by

`cos(theta)=(vec A * vec B)/(|vec A| * |vec B|)`

1. Calculate dot product
`vec A * vec B`

`=A_1*B_1+A_2*B_2+A_3*B_3`

`=3*2+4*2+0*1`

`=6+8`

`=14`

2. Calculate magnitude of vectors
`|vec A|`

`=sqrt(A_1^2 + A_2^2 + A_3^2)`

`=sqrt(3^2 + 4^2 + 0^2)`

`=sqrt(9 + 16 + 0)`

`=sqrt(25)`

`=5`


`|vec B|`

`=sqrt(B_1^2 + B_2^2 + B_3^2)`

`=sqrt(2^2 + 2^2 + 1^2)`

`=sqrt(4 + 4 + 1)`

`=sqrt(9)`

`=3`


3. Calculate angle between vectors
`cos(theta)=(vec A * vec B)/(|vec A| * |vec B|)=(14)/(5 * 3)=14/15`

`:. theta=cos^(-1)(14/15)`

`:. theta=0.3672` rad Or `theta=21.0395 ^circ`

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