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Home > Word Problems calculators > Percentage Word Problems example
Percentage examples ( Enter your problem )
( Enter your problem )
 
  1. Example-1
 		Other related methods
  1. Statistics Word Problem
  2. HCF-LCM Word Problem
  3. Percentage
  4. Profit Loss Discount
  5. Simple Interest
  6. Compound Interest
  7. Installment
  8. Arithmetic Progression
  9. Geometric Progression
2. HCF-LCM Word Problem
(Previous method)		4. Profit Loss Discount
(Next method)

1. Example-1
Problem : 1 / 12 [ Percentage ]       Enter your problem
1. What is 20 % of 80 .
Solution: `20` % of `80 = 20 / 100 × 80 = 16`.

Problem : 2 / 12 [ Percentage ]       Enter your problem
2. 42 is 3 % of what.
Solution: Let `42` is `3` % of X

`3 / 100 × X = 42`

`=> X = 42 × 100/3`

`=> X = 1400` .

Problem : 3 / 12 [ Percentage ]       Enter your problem
3. What percent of 65 is 130 .
Solution: Let X % of `65` is `130`

`=> X/100 × 65 = 130`

`=> X = (130 × 100 )/65`

`=> X = 200` %

Problem : 4 / 12 [ Percentage ]       Enter your problem
4. 130 is what percent of 65 .
Solution: Let X % of `65` is `130`

`=> X/100 × 65 = 130`

`=> X = (130 × 100 )/65`

`=> X = 200` %

Problem : 5 / 12 [ Percentage ]       Enter your problem
5. What is the percentage increase/decrease from 20 to 40 ?

Problem : 6 / 12 [ Percentage ]       Enter your problem
6. A's annual income is increased/decreased from Rs 60000 to Rs 75000 . Find the percentage of increase in A's income.
Solution: A's original income = Rs `60000`

A's new income = Rs `75000`

`=>` Increase = Rs `15000`

`=>` Increase % = `("Increase")/"Original Income" × 100 = 15000 / 60000 × 100 = 25`

A's income is increased by `25` %

Problem : 7 / 12 [ Percentage ]       Enter your problem
7. In a school of 225 boys, 15 were absent then what percent were present ?
Solution: In a school of `225` boys, `15` were absent

`:. 225 - 15 = 210` were present

`:.` present % = `210 / 225 × 100 = 93.3333` %

Problem : 8 / 12 [ Percentage ]       Enter your problem
8. A earns 25 % more than B. By what percent does B earn less then A.
Solution: Let A's income = Rs `100`

`:.` B's income = Rs `( 100 + 25 )` = Rs `125`

B's Income Rs A's Income Rs
125 100
100?

A's Income = `( 100 × 100 ) / 125 = 80` Rs

`:.` A's income is Rs `20` less than by B's income (Rs `100`)

`:.` A's income is `20` % less than by B's income.

Problem : 9 / 12 [ Percentage ]       Enter your problem
9. A reduction of 20 % in the price of basmati rice would enable a man to buy 2 kg of rice more for Rs 250 . Find the reduced price per kg.
Solution: A reduction of `20` % in the price of basmati rice would enable a man to buy `2` kg of rice more for Rs `250` .

`:.` Reduced price of `2` kg rice = `20` % of Rs `250 = 20 / 100 × 250 = 50`

`:.` Reduced price of `2` kg rice = Rs `50`

`:.` Reduced price of per kg rice = Rs `25`

Problem : 10 / 12 [ Percentage ]       Enter your problem
10. The price of tea has gone up by 20 %. By how much percent should its consumption be reduced so as not to increase the expenditure?
Solution: Let price of tea be Rs `100` per kg

`:.` new price of tea = Rs `( 100 + 20 )` = Rs `120` per kg

Now not to increase the expenditure, its consumption must be reduced by Rs `20`

New Price RsReduced Consumption Rs
120 20
100?

Reduced Consumption = `(100 × 20) / 120 = 16.6667` Rs

`:.` Consumption must be reduced by Rs `16.6667` , if original price of tea be Rs `100`

`:.` Consumption must be reduced by `16.6667` % for not to increase the expenditure.

Problem : 11 / 12 [ Percentage ]       Enter your problem
11. Find the selling price of an item, of which the printed price is Rs 25000 if the successive discounts given are 10 %, 8 % and 4 %.
Solution: Here, printed price of an item = `25000`

The amount paid by customer = `90` % of `92` % of `96` % of `25000`

`:.` amount after discounts = `25000 × 90 / 100 × 92 / 100 × 96 / 100`

`:.` amount after discounts = `19872`

Hence selling price of an item is Rs `19872` .

Problem : 12 / 12 [ Percentage ]       Enter your problem
12. The successive discount of 10 % and 5 % are given on the purchased Computer. If the final price of the Computer is Rs 10260 , then find the printed price of the Computer.
Solution: Let the printed price of computer be Rs `X`

The amount paid by customer = `90` % of `95` % of `X`

`:.` amount after both the discounts `= X × 90 / 100 × 95 / 100`

`:. 10260 = X × 90 / 100 × 95 / 100`

`:. X = (10260 × 100 × 100 ) / (90 × 95) = 12000`

Hence printed price of the computer is Rs `12000`.

2. HCF-LCM Word Problem
(Previous method)		4. Profit Loss Discount
(Next method)


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