1. Find Laspeyre's index number, Paasche's index number, Fisher's index number

Item	Price0	Quantity0	Price1	Quantity1
Rice	39	1	40	1.5
Milk	40	12	44	10
Bread	45	2	50	1.5
Banana	30	2	36	1.5

Solution:

Item	`p_0`	`q_0`	`p_1`	`q_1`	`p_1q_0`	`p_0q_0`	`p_1q_1`	`p_0q_1`
Rice	39	1	40	1.5	40	39	60	58.5
Milk	40	12	44	10	528	480	440	400
Bread	45	2	50	1.5	100	90	75	67.5
Banana	30	2	36	1.5	72	60	54	45
---	---	---	---	---	---	---	---	---
Total					`740`	`669`	`629`	`571`

1. Laspeyre's index number

`I_L=(sum p_1q_0)/(sum p_0q_0) xx 100`

`=(740)/(669) xx 100`

`=110.61`

Thus, there is a rise of `(110.61-100)=10.61%` in prices

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2. Paasche's index number

`I_P=(sum p_1q_1)/(sum p_0q_1) xx 100`

`=(629)/(571) xx 100`

`=110.16`

Thus, there is a rise of `(110.16-100)=10.16%` in prices

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3. Fisher's index number

`I_F=sqrt(I_L xx I_P)`

`=sqrt(110.6129 xx 110.1576)`

`=110.39`

Thus, there is a rise of `(110.39-100)=10.39%` in prices

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