1. Find Marshall Edgeworth's index number

Item	Price0	Quantity0	Price1	Quantity1
Rice	39	1	40	1.5
Milk	40	12	44	10
Bread	45	2	50	1.5
Banana	30	2	36	1.5

Solution:

Item	`p_0`	`q_0`	`p_1`	`q_1`	`p_1q_0`	`p_0q_0`	`p_1q_1`	`p_0q_1`
Rice	39	1	40	1.5	40	39	60	58.5
Milk	40	12	44	10	528	480	440	400
Bread	45	2	50	1.5	100	90	75	67.5
Banana	30	2	36	1.5	72	60	54	45
---	---	---	---	---	---	---	---	---
Total					`740`	`669`	`629`	`571`

1. Marshall Edgeworth index number

`I_M=(sum p_1q_0+sum p_1q_1)/(sum p_0q_0+sum p_0q_1) xx 100`

`=(740+629)/(669+571) xx 100`

`=(1369)/(1240) xx 100`

`=110.4`

Thus, there is a rise of `(110.4-100)=10.4%` in prices

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2. Find Marshall Edgeworth's index number

Item	Price0	Quantity0	Price1	Quantity1
A	10	20	12	22
B	8	16	8	18
C	5	10	6	11
D	4	7	4	8

Solution:

Item	`p_0`	`q_0`	`p_1`	`q_1`	`p_1q_0`	`p_0q_0`	`p_1q_1`	`p_0q_1`
A	10	20	12	22	240	200	264	220
B	8	16	8	18	128	128	144	144
C	5	10	6	11	60	50	66	55
D	4	7	4	8	28	28	32	32
---	---	---	---	---	---	---	---	---
Total					`456`	`406`	`506`	`451`

1. Marshall Edgeworth index number

`I_M=(sum p_1q_0+sum p_1q_1)/(sum p_0q_0+sum p_0q_1) xx 100`

`=(456+506)/(406+451) xx 100`

`=(962)/(857) xx 100`

`=112.25`

Thus, there is a rise of `(112.25-100)=12.25%` in prices

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3. Find Marshall Edgeworth's index number

Item	Price0	Quantity0	Price1	Quantity1
A	3	25	5	28
B	1	50	3	60
C	2	30	1	30
D	5	15	6	12

Solution:

Item	`p_0`	`q_0`	`p_1`	`q_1`	`p_1q_0`	`p_0q_0`	`p_1q_1`	`p_0q_1`
A	3	25	5	28	125	75	140	84
B	1	50	3	60	150	50	180	60
C	2	30	1	30	30	60	30	60
D	5	15	6	12	90	75	72	60
---	---	---	---	---	---	---	---	---
Total					`395`	`260`	`422`	`264`

1. Marshall Edgeworth index number

`I_M=(sum p_1q_0+sum p_1q_1)/(sum p_0q_0+sum p_0q_1) xx 100`

`=(395+422)/(260+264) xx 100`

`=(817)/(524) xx 100`

`=155.92`

Thus, there is a rise of `(155.92-100)=55.92%` in prices

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