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5. Weighted Index Numbers example ( Enter your problem )
  1. Laspeyre's index number Example-1
  2. Paasche's index number Example-2
  3. Fisher's index number Example-3
  4. Marshall Edgeworth's index numberExample-4
  5. Dorbish-Bowley's index number Example-5
  6. Kelly's index number Example-6
  7. Walsh's index number Example-7

3. Fisher's index number Example-3





1. Find Fisher's index number
ItemPrice0Quantity0Price1Quantity1
Rice391401.5
Milk40124410
Bread452501.5
Banana302361.5


Solution:
Item`p_0``q_0``p_1``q_1``p_1q_0``p_0q_0``p_1q_1``p_0q_1`
Rice391401.540396058.5
Milk40124410528480440400
Bread452501.5100907567.5
Banana302361.572605445
---------------------------
Total`740``669``629``571`


1. Fisher's index number

`I_F=sqrt((sum p_1q_0)/(sum p_0q_0) xx (sum p_1q_1)/(sum p_0q_1)) xx 100`

`=sqrt((740)/(669) xx (629)/(571)) xx 100`

`=sqrt(1.2185) xx 100`

`=1.1039 xx 100`

`=110.39`

Thus, there is a rise of `(110.39-100)=10.39%` in prices
2. Find Fisher's index number
ItemPrice0Quantity0Price1Quantity1
A10201222
B816818
C510611
D4748


Solution:
Item`p_0``q_0``p_1``q_1``p_1q_0``p_0q_0``p_1q_1``p_0q_1`
A10201222240200264220
B816818128128144144
C51061160506655
D474828283232
---------------------------
Total`456``406``506``451`


1. Fisher's index number

`I_F=sqrt((sum p_1q_0)/(sum p_0q_0) xx (sum p_1q_1)/(sum p_0q_1)) xx 100`

`=sqrt((456)/(406) xx (506)/(451)) xx 100`

`=sqrt(1.2601) xx 100`

`=1.1226 xx 100`

`=112.26`

Thus, there is a rise of `(112.26-100)=12.26%` in prices
3. Find Laspeyre's index number, Paasche's index number, Fisher's index number
ItemPrice0Quantity0Price1Quantity1
A325528
B150360
C230130
D515612


Solution:
Item`p_0``q_0``p_1``q_1``p_1q_0``p_0q_0``p_1q_1``p_0q_1`
A3255281257514084
B1503601505018060
C23013030603060
D51561290757260
---------------------------
Total`395``260``422``264`


1. Laspeyre's index number

`I_L=(sum p_1q_0)/(sum p_0q_0) xx 100`

`=(395)/(260) xx 100`

`=151.92`

Thus, there is a rise of `(151.92-100)=51.92%` in prices



2. Paasche's index number

`I_P=(sum p_1q_1)/(sum p_0q_1) xx 100`

`=(422)/(264) xx 100`

`=159.85`

Thus, there is a rise of `(159.85-100)=59.85%` in prices



3. Fisher's index number

`I_F=sqrt(I_L xx I_P)`

`=sqrt(151.9231 xx 159.8485)`

`=155.84`

Thus, there is a rise of `(155.84-100)=55.84%` in prices




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