11. Reverse of the square, cube, prime type series
1. Find next 3 numbers in the sequence `61,52,63,94,46`
Here each number is reverse of the square of the numbers
`4^2=16 => 61`
`5^2=25 => 52`
`6^2=36 => 63`
`7^2=49 => 94`
`8^2=64 => 46`
So required number are
`9^2=81 => 18`
`10^2=100 => 001`
`11^2=121 => 121`
Answer : `18,001,121`
`:.` The next 3 number for given series `61,52,63,94,46` are `18,001,121`
Solution-1
2. Find next 3 numbers in the sequence `1,4,9,61,52`
Here each number is reverse of the square of the numbers
`1^2=1 => 1`
`2^2=4 => 4`
`3^2=9 => 9`
`4^2=16 => 61`
`5^2=25 => 52`
So required number are
`6^2=36 => 63`
`7^2=49 => 94`
`8^2=64 => 46`
Answer : `63,94,46`
`:.` The next 3 number for given series `1,4,9,61,52` are `63,94,46`
Solution-1
3. Find next 3 numbers in the sequence `72,46,521,612,343`
Here each number is reverse of the cube of the numbers
`3^3=27 => 72`
`4^3=64 => 46`
`5^3=125 => 521`
`6^3=216 => 612`
`7^3=343 => 343`
So required number are
`8^3=512 => 215`
`9^3=729 => 927`
`10^3=1000 => 0001`
Answer : `215,927,0001`
`:.` The next 3 number for given series `72,46,521,612,343` are `215,927,0001`
Solution-1
4. Find next 3 numbers in the sequence `11,31,71,91,32,92`
Here each number is reverse of the prime number
`5" prime "=11 => 11`
`6" prime "=13 => 31`
`7" prime "=17 => 71`
`8" prime "=19 => 91`
`9" prime "=23 => 32`
`10" prime "=29 => 92`
So required number are
`11" prime "=31 => 13`
`12" prime "=37 => 73`
`13" prime "=41 => 14`
Answer : `13,73,14`
`:.` The next 3 number for given series `11,31,71,91,32,92` are `13,73,14`
Solution-1
5. Find next 3 numbers in the sequence `18,46,94,63`
`18,46,94,63,...`
First reverse the digits of each number
`81,64,49,36,...`
Here each number is square of numbers in descending order
The next term will be `25,16,9`
So after reversing it, the answer will be `52,61,9`
`:.` The next 3 number for given series `18,46,94,63` are `52,61,9`
Solution-1
6. Find next 3 numbers in the sequence `215,343,612,521,46`
`215,343,612,521,46,...`
First reverse the digits of each number
`512,343,216,125,64,...`
Here each number is cube of the numbers in descending order
The next term will be `27,8,1`
So after reversing it, the answer will be `72,8,1`
`:.` The next 3 number for given series `215,343,612,521,46` are `72,8,1`
Solution-1
This material is intended as a summary. Use your textbook for detail explanation.
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