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Percentile for grouped data Example-3 ( Enter your problem )
  1. Formula & Example-1
  2. Example-2
  3. Example-3

3. Example-3





5. Calculate Percentiles-20 from the following grouped data
ClassFrequency
10 - 2015
20 - 3025
30 - 4020
40 - 5012
50 - 608
60 - 705
70 - 803


Solution:
ClassFrequency
`f`
`cf`
10 - 201515
20 - 302540
30 - 402060
40 - 501272
50 - 60880
60 - 70585
70 - 80388
---------
n = 88--


Here, `n = 88`


`P_20` class :

Class with `((20n)/100)^(th)` value of the observation in `cf` column

`=((20*88)/100)^(th)` value of the observation in `cf` column

`=(17.6)^(th)` value of the observation in `cf` column

and it lies in the class `20 - 30`.

`:. P_20` class : `20 - 30`

The lower boundary point of `20 - 30` is `20`.

`:. L = 20`

`P_20 = L + ((20 n)/100 - cf)/f * c`

`=20 + (17.6 - 15)/25 * 10`

`=20 + (2.6)/25 * 10`

`=20 + 1.04`

`=21.04`


6. Calculate Percentiles-70 from the following grouped data
ClassFrequency
20 - 25110
25 - 30170
30 - 3580
35 - 4045
40 - 4540
45 - 5035


Solution:
ClassFrequency
`f`
`cf`
20 - 25110110
25 - 30170280
30 - 3580360
35 - 4045405
40 - 4540445
45 - 5035480
---------
n = 480--


Here, `n = 480`


`P_70` class :

Class with `((70n)/100)^(th)` value of the observation in `cf` column

`=((70*480)/100)^(th)` value of the observation in `cf` column

`=(336)^(th)` value of the observation in `cf` column

and it lies in the class `30 - 35`.

`:. P_70` class : `30 - 35`

The lower boundary point of `30 - 35` is `30`.

`:. L = 30`

`P_70 = L + ((70 n)/100 - cf)/f * c`

`=30 + (336 - 280)/80 * 5`

`=30 + (56)/80 * 5`

`=30 + 3.5`

`=33.5`




This material is intended as a summary. Use your textbook for detail explanation.
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