3. Calculate Quartile-3 from the following grouped data
| Class | Frequency |
| 2 - 4 | 3 |
| 4 - 6 | 4 |
| 6 - 8 | 2 |
| 8 - 10 | 1 |
Solution:| Class | Frequency `f` | `cf` |
| 2 - 4 | 3 | 3 |
| 4 - 6 | 4 | 7 |
| 6 - 8 | 2 | 9 |
| 8 - 10 | 1 | 10 |
| --- | --- | --- |
| n = 10 | -- |
Here, `n = 10`
`Q_3` class :
Class with `((3n)/4)^(th)` value of the observation in `cf` column
`=((3*10)/4)^(th)` value of the observation in `cf` column
`=(7.5)^(th)` value of the observation in `cf` column
and it lies in the class `6 - 8`.
`:. Q_3` class : `6 - 8`
The lower boundary point of `6 - 8` is `6`.
`:. L = 6`
`Q_3 = L + ((3 n)/4 - cf)/f * c`
`=6 + (7.5 - 7)/2 * 2`
`=6 + (0.5)/2 * 2`
`=6 + 0.5`
`=6.5`
4. Calculate Quartile-1 from the following grouped data
| Class | Frequency |
| 0 - 2 | 5 |
| 2 - 4 | 16 |
| 4 - 6 | 13 |
| 6 - 8 | 7 |
| 8 - 10 | 5 |
| 10 - 12 | 4 |
Solution:| Class | Frequency `f` | `cf` |
| 0 - 2 | 5 | 5 |
| 2 - 4 | 16 | 21 |
| 4 - 6 | 13 | 34 |
| 6 - 8 | 7 | 41 |
| 8 - 10 | 5 | 46 |
| 10 - 12 | 4 | 50 |
| --- | --- | --- |
| n = 50 | -- |
Here, `n = 50`
`Q_1` class :
Class with `(n/4)^(th)` value of the observation in `cf` column
`=(50/4)^(th)` value of the observation in `cf` column
`=(12.5)^(th)` value of the observation in `cf` column
and it lies in the class `2 - 4`.
`:. Q_1` class : `2 - 4`
The lower boundary point of `2 - 4` is `2`.
`:. L = 2`
`Q_1 = L + (( n)/4 - cf)/f * c`
`=2 + (12.5 - 5)/16 * 2`
`=2 + (7.5)/16 * 2`
`=2 + 0.9375`
`=2.9375`
This material is intended as a summary. Use your textbook for detail explanation.
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