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Quintile for grouped data Example-2 ( Enter your problem )
  1. Formula & Example-1
  2. Example-2
  3. Example-3

2. Example-2





3. Calculate Quintile-4 from the following grouped data
ClassFrequency
2 - 43
4 - 64
6 - 82
8 - 101


Solution:
ClassFrequency
`f`
`cf`
2 - 433
4 - 647
6 - 829
8 - 10110
---------
`n = 10`--


Here, `n = 10`


`"Quintile"_4` class :

Class with `((4n)/5)^(th)` value of the observation in `cf` column

`=((4*10)/5)^(th)` value of the observation in `cf` column

`=(8)^(th)` value of the observation in `cf` column

and it lies in the class `6 - 8`.

`:. "Quintile"_4` class : `6 - 8`

The lower boundary point of `6-8` is `6`.

`:. L=6`

`"Quintile"_4=L+((4 n)/5 - cf)/f * c`

`=6+(8-7)/2*2`

`=6+(1)/2*2`

`=6+1`

`=7`


4. Calculate Quintile-3 from the following grouped data
ClassFrequency
0 - 25
2 - 416
4 - 613
6 - 87
8 - 105
10 - 124


Solution:
ClassFrequency
`f`
`cf`
0 - 255
2 - 41621
4 - 61334
6 - 8741
8 - 10546
10 - 12450
---------
`n = 50`--


Here, `n = 50`


`"Quintile"_3` class :

Class with `((3n)/5)^(th)` value of the observation in `cf` column

`=((3*50)/5)^(th)` value of the observation in `cf` column

`=(30)^(th)` value of the observation in `cf` column

and it lies in the class `4 - 6`.

`:. "Quintile"_3` class : `4 - 6`

The lower boundary point of `4-6` is `4`.

`:. L=4`

`"Quintile"_3=L+((3 n)/5 - cf)/f * c`

`=4+(30-21)/13*2`

`=4+(9)/13*2`

`=4+1.3846`

`=5.3846`






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