Find Row Space ...
`[[3,-1,-1],[2,-2,1]]`

Solution:

	`3`	`-1`	`-1`
	`2`	`-2`	`1`

Now, reduce the matrix to reduced row echelon form
`R_1 larr R_1-:3`

=	`1` `-1/3` `-1/3` `2` `-2` `1`

`R_2 larr R_2-2xx R_1`

=	`1` `-1/3` `-1/3` `0` `-4/3` `5/3`

`R_2 larr R_2xx-3/4`

=	`1` `-1/3` `-1/3` `0` `1` `-5/4`

`R_1 larr R_1+1/3xx R_2`

=	`1` `0` `-3/4` `0` `1` `-5/4`

The rank of a matrix is the number of non all-zeros rows
`:. Rank = 2`

Row Space :
The nonzero rows in the reduced row-echelon form are a basis for the row space of the matrix
`[[1,0,-3/4]],`

`[[0,1,-5/4]]`

---