Find Row Space ...
`[[1,2,3,2],[3,0,1,8],[2,-2,-2,6]]`

Solution:

	`1`	`2`	`3`	`2`
	`3`	`0`	`1`	`8`
	`2`	`-2`	`-2`	`6`

Now, reduce the matrix to reduced row echelon form
interchanging rows `R_1 harr R_2`

=	`3` `0` `1` `8` `1` `2` `3` `2` `2` `-2` `-2` `6`

`R_1 larr R_1-:3`

=	`1` `0` `1/3` `8/3` `1` `2` `3` `2` `2` `-2` `-2` `6`

`R_2 larr R_2- R_1`

=	`1` `0` `1/3` `8/3` `0` `2` `8/3` `-2/3` `2` `-2` `-2` `6`

`R_3 larr R_3-2xx R_1`

=	`1` `0` `1/3` `8/3` `0` `2` `8/3` `-2/3` `0` `-2` `-8/3` `2/3`

`R_2 larr R_2-:2`

=	`1` `0` `1/3` `8/3` `0` `1` `4/3` `-1/3` `0` `-2` `-8/3` `2/3`

`R_3 larr R_3+2xx R_2`

=	`1` `0` `1/3` `8/3` `0` `1` `4/3` `-1/3` `0` `0` `0` `0`

The rank of a matrix is the number of non all-zeros rows
`:. Rank = 2`

Row Space :
The nonzero rows in the reduced row-echelon form are a basis for the row space of the matrix
`[[1,0,1/3,8/3]],`

`[[0,1,4/3,-1/3]]`

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