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8. LU decomposition using Gauss Elimination method of matrix example ( Enter your problem )
  1. Example `[[8,-6,2],[-6,7,-4],[2,-4,3]]`
  2. Example `[[3,2,4],[2,0,2],[4,2,3]]`
  3. Example `[[1,1,1],[-1,-3,-3],[2,4,4]]`
  4. Example `[[2,3],[4,10]]`

3. Example `[[1,1,1],[-1,-3,-3],[2,4,4]]`





Find LU Decomposition using Gauss Elimination method of Matrix ...
`[[1,1,1],[-1,-3,-3],[2,4,4]]`


Solution:
`LU` decomposition : If we have a square matrix A, then an upper triangular matrix U can be obtained without pivoting under Gaussian Elimination method, and there exists lower triangular matrix L such that A=LU.


Here `A` = 
`1``1``1`
`-1``-3``-3`
`2``4``4`


Using Gaussian Elimination method
`R_2 larr R_2-``(-1)``xx R_1` `[:.L_(2,1)=color{blue}{-1}]`

 = 
`1``1``1`
`0``-2``-2`
`2``4``4`


`R_3 larr R_3-``(2)``xx R_1` `[:.L_(3,1)=color{blue}{2}]`

 = 
`1``1``1`
`0``-2``-2`
`0``2``2`


`R_3 larr R_3-``(-1)``xx R_2` `[:.L_(3,2)=color{blue}{-1}]`

 = 
`1``1``1`
`0``-2``-2`
`0``0``0`


`:.U` = 
`1``1``1`
`0``-2``-2`
`0``0``0`


`L` is just made up of the multipliers we used in Gaussian elimination with 1s on the diagonal.

`:.L` = 
`1``0``0`
`color{blue}{-1}``1``0`
`color{blue}{2}``color{blue}{-1}``1`


Now checking `A=LU` ?

`LU` = 
`1``0``0`
`-1``1``0`
`2``-1``1`
 `xx` 
`1``1``1`
`0``-2``-2`
`0``0``0`
 = 
`1``1``1`
`-1``-3``-3`
`2``4``4`


And `A` = 
`1``1``1`
`-1``-3``-3`
`2``4``4`


Solution is possible.




This material is intended as a summary. Use your textbook for detail explanation.
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